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It working perfectly fine. Can I know what that AWK does please explain i have to brief my coworker

How to delete the duplicates using this?

I am using the below script to delete duplicate files but it is not working for directories with more than 10k files "Argument is too long" is getting for ls -t. Tried to replace ls -t with

find ....

I have prepared a shell script to find the duplicates based on the part of filename and retain latest.

#!/bin/bash
if [ ! -d dup ]; then
mkdir -p dup
fi
NOW=$(date...

I have prepared a script with ls -t to fetch latest file and compare with duplicates i use below

ls -t *xml |awk 'BEGIN{FS="_"}{if (++dup[$1] >= 2) print}'

However for large size folder ls...

I have a folder with series of filename patterns like the below.
./ARCZ00300_010117_1504690829222.xml
./ARCZ00300_010117_1507101655366.xml [latest]
./ARCZ00301_010117_1504691829478.xml...

I have tried the following code and with that i couldnt achieve what i want.

#!/usr/bin/bash
find ./ -type f \( -iname "*.xml" \) | sort -n > fileList
sed -i '/\.\/fileList/d'...