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i am on red hat Linux .



package hiveudf;
import org.apache.hadoop.hive.ql.exec.UDF;
import org.apache.hadoop.io.Text;
public class lowercaseudf extends UDF {
public Text...

sorry the browswer not putting code tags around the code when I click on button , so I am adding them manually hope it works.
can someone help me on my sed command please?

I am using sun...

sorry I messed up the last post with too many mistakes and corrections so I closed it and opening a new one which should be clear to everyone .my apologies to the admins.


I am using sun solaris...

Rudi's sed is not returning me anything


$ type a.txt
000000001000
433483433339
121121211100
167710000110
167735250310
167735260510
167735280710
167735301010
167735431010
167735451010...

ok let me tell it more clearly ..lets say I have a file a.txt
$ type a.txt
000000001000
433483433339 record 2
121121211100
167710000110
167735250310
167735260510
167735280710
167735431010...

hi Rudi .. sorry it was a typo. . 2nd wrong is not wrong. but 1st wrong is wrong.
I ran your command it selects nothing ?



------ Post updated at 09:12 PM ------



no i dont want to...

I want to match all occurrence of 01,03,05,07,10,11 at 9th and 10th position of a string .
I tried the following but its also matching characters like 33 or 11 on 9th and 10th position .


sed ...

thanks

is it possible to break out of sed on the first non match instead of looping through the whole large file ?

i have a large file where i want to look for any record that is is larger or smaller than 21 and if it is the case i want to report and break SED .. how can i achieve it ?
i dont want sed to...

no it didnt help .. if i try to use "!" i get unknown command :(

sed -n '!/^.\{20,21\}$/p' a.a
sed: Unknown command

---------- Post updated at 12:54 PM ---------- Previous update was at...

i am using sed to detect any lines that are not exactly 21. the following gives me the lines that ARE exactly 21. i want the opposite , i want the two lines that are not size 21 (shown in bold)

...

btw is it possible to just end the sed command even if one nomatching record is found ? i have a large file to search these records and its taking long time to come out .

its giving me all the records ?
e.g in the data below i only want the highlighted record since its 9th and 10th position DO NOT contain either 01,03,05,07

-bash-4.4$ more a.a...

i have this data where i am looking for a two digit number 01,03,05 or 07.
if not found i should detect that .

this sed command gives me the matching rows . I want the opposite , i want the rows...

iam withdrawing this thread , It was my mistake I didn't read the code properly