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Hello RavinderSingh13,

I tried to execute above code. But i did not receive FileDate.
Here is the sample output I got


DATE MOVED FileDate Count Size
Jan15 106 ...

I have file listed in my directory in following format


-rwxrwxr-x+ 1 test test 4.9M Oct 3 16:06 test20141002150108.txt
-rwxrwxr-x+ 1 test test 4.9M Oct 4 16:06...

You can get some idea using following url

https://www.unix.com/shell-programming-and-scripting/253499-script-determine-date-totalfile-total-size-file-based-date.html

Thanks Don!!!

Tested and getting expected result


DATE TOTALFILE TOTALSIZE
Nov26 2 17506702
Nov27 26 2429166955
Dec1 1 133

Yes you are correct Panyam. i am doing ls -lrth . In my script you can see that.

I have file listed like below

-rw-r--r--+ 1 test test 17M Nov 26 14:43 test1.gz
-rw-r--r--+ 1 test test 0 Nov 26 14:44 test2.gz
-rw-r--r--+ 1 test test 0 Nov 27 10:41 test3.gz...

Thanks Don Cragun for your reply..

Surly I will do that and monitor. Any issue i face let you know...

Already i am trying to achieve this by below script

# Go to the directory from where want to copy files

cd /mydir
find . -type f -mtime 1 -exec cp {} /destdir\;
find . -type f -mtime 1 -exec...

I have bunch of files in my source folder like below and every day based on date I am receiving file ex: Nov 28,Nov 29,Nov 30 ...

-rw-rw-r--+ 1 root root 20 Nov 27 06:00 aaaa27.txt
-rw-rw-r--+ 1...

Hi All,
Thanks for your reply.
can you please help me to print particular column name as well.

@Ahamed101
can you please explain your code.

Here is my sample data
Test.txt


column 1|columne 2|columne 3|columne 4
test|test||test
test|test|test|
test||test|test
test|test|test|test
|test|test|test


In that example having NULL...

Thanks RavinderSingh13 and anbu23

Here is my sample data
Test.txt

column 1|columne 2|start Date|end Date
test|test|03/24/2014|03/24/2014
test|test|03/24-2014|03/24/2014
test|test|03/24/2014|03/24/2014...