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You can try this, it is probably a lot more complicated that in needs to be but it seems to work. It trims the leading spaces before \Start as well so if that is undesired then it can be changed.
...

set is a shell built in. It can be used to define environmental variables however in this instance it is being used to evaluate positional parameters based upon what * expands to. For example, if *...

Thanks for all the great replies guys. I enjoyed playing about with your script Don!

You can turn this into a little 'find the hidden character' type game to. For example, find the hidden $ in a...

Wow Scrutinizer, very nice! Now I have to try and get my head round your code :)

Hey guys,

This is purely just a little bit of fun with awk. I realize this this isn't that constructive so please remove if need be.

Your goal:
Create a one line awk script that generates a...

What have you tried so far? Can you provide some sample input data/desired output data?

Try:

awk '($2>=10 && $2<=20) || ($3>=10 && $3<=20)' file

The following assumptions have been made based upon your output:
- If $2 OR $3 are within the min/max range, then print the row. Not $2...

Try:

for fichier in fichier1 fichier2 fichier3; do
if [[ -e ${fichier} ]]; then
Pgsql
else
echo \nLe fichier ${fichier} n\'existe pas ;
fi
done

Depending on your shell you could do something like:

echo ${line/*[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-3][0-9] [0-9][0-9]:[0-9][0-9]:[0-9][0-9],[0-9][0-9][0-9]/}

Try:

awk 'f{gsub(/[[:lower:]]/,toupper($0));f=0};NF{f=1}1' file

Thanks Akshay - Amended now!

Another solution:

printf "%s|%s\n" $(wc -l file.txt asdf.txt lkjh.txt bvcx.txt|sed '$d') >> temp.txt

Try:

awk 'FNR==1&&p{print p};{p=FNR"|"FILENAME};END{print FNR"|" FILENAME}' file.txt asdf.txt lkjh.txt bvcx.txt >> temp.txt

@Kanja

No assumptions have been made - only answers based upon your input data/expected output

awk 'NR==FNR&&NR>1 # Whilst the condition NR==FNR is true (which it will only be for the first file being read) and NR is greater than 1
{A[$2]=$NF;next}; # Build an array where the index is the...

Try:

awk 'NR==FNR&&NR>1{A[$2]=$NF;next};($2 in A){print $0,A[$2]}' file2 file1

In the 2nd column of your 2nd line you have the number 269. In your output you have got 265, shouldn't this be 268?

The below is a pure shell solution:

f=0 ; while read -r one two three; do
...

Can you also post the expected output please?

I am seeing it also

It would all depend upon the number of lines the code is traversing.

What about a while loop?

COUNTPRO2="gine is very bad
vine is pretty good"

echo "${COUNTPRO2}" | while read line; do
[[ $line == *"vine"* ]] && echo $line
done

Sorry about that, I've amended the script slightly so it should work as expected now:

#!/bin/bash
FILESDIR=/home/cmccabe/Desktop/files
ANNOVARDIR=/home/cmccabe/Desktop/annovar

PS3="please...

Nice one Scrutinizer!!!

Hi - This is only rough but something like the below should work on your data:

#!/bin/bash
FILESDIR=/home/cmccabe/Desktop/files
ANNOVARDIR=/home/cmccabe/Desktop/annovar

PS3="please select a...

That method is quite an overkill by the looks of it. You could simply do something like this (providing you have an bash/ksh that supports this form of parameter expansion):


fs="/one/two/three/"...