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Try a > && < instead of == in the awk statement.

Here's an option, assuming there's no spaces in the file names:find . -type f -mtime -1 -printf '%f %TH%TM\n' | awk '$NF=="1845" {print $1}'

Instead of using sequentially named variables, why not use a list (if you don't need to start with 19), or a dict?child = {}
child[19] = 'value 19'
child[20] = 'value 20'

for x in range(19,20):...

... if perl is an option:perl -0777 -pe 's/==Image Gallery==.?<gallery>.*?<\/gallery>\s?//gs' file

Here's another option:join -t'~' -v1 <(sed 's/\t/~/2' file1|sort) file2 | tr '~' '\t'

EDIT:join -t'~' -v1 <(sed 's/ /~/2' file1|sort) file2 | tr '~' ' '

Based on your given input & desired output, couldn't you just use:join -t',' file1 file2

awk '
$2=="CD" {
key=$5"|"$9"|";
($3>A[key"max"] || A[key"max"]=="")? A[key"max"]=$3:"";
($4>A[key"max"] || A[key"max"]=="")? A[key"max"]=$4:"";
($3<A[key"min"] || A[key"min"]=="")?...

awk '
NR%2 {match($0,/ [0-9]+ /); n=substr($0,RSTART,RLENGTH); next}
{print $0, n}
' file

Another option would be to just check the filename:awk '
BEGIN {f=FILENAME}
FILENAME==f {A[$1]; f=FILENAME; next}
($1 in A)
' file1 file2

The ultra-short-code-hackers can even use:awk '...

awk -F, '{print "totalamount :"$1, "Count:" $2}' OFS='\n' file

awk -F'|' 'NR==FNR {split($5,a,","); for(i in a) {A[a[i]]++; $5=a[i]; print $0 >> "file.tmp"}} NR!=FNR && (FNR==1 || A[$5]>1)' OFS='|' file file.tmp && rm file.tmp

... on a side note, the ternary isn't necessary:awk '/^@/{s=/192\.2\.3/}s' file

It's worth noting that Don's example won't match if inside the quotes a comma is the first character. Since \K doesn't seem to work with the VB Regexp object, you could utilize a look-ahead assertion...

So why ask for help in a UNIX/Linux forum?

Anyways, as Don already pointed out, Parsing based on double quotes is what I'd do. But, if you want just a strait regex solution, the following needle...

Please post some concrete requests. You keep changing the source data. Or, better yet, how about learning from the posted code & adapting it to meet your needs?

Remove the red line to keep the dots, rather than dashes:
perl -F'\s|,' -ane '$\=",";
for $i (0..$#F) {
@s=split(/:/,$F[$i]);
if($i<=1) {
$s[0]=~s/\./-/g;
print $s[0].($i==1?...

awk 'NR==FNR {a[$1]=$2; next} $1 in a {print $0, a[$1]}' file2 file1

also ...for i in `seq 1 $n`; do echo $i; done... though you don't need the 1 since you're starting at 1.

$line=~/.*,(.*?\w)-\w/; print "$1\n"

For my reference ...
... can you provide an example?

... what would be the threshold? Would gawk perform better?

awk 'NR>1 {print > (OFN=FILENAME"."(NR-1)); close(OFN)}' RS="--dump[^\n]*" file

EDIT:
... implemented this above ...

... a basic awk approach ...awk '
$0~/IN:CTRL=/ {f="I"; i++}
$0~/OUT:CTRL=/ {f="O"; o++}
f=="I" {IN[i]=IN[i] RS $0}
f=="O" {OUT[o]=OUT[o] RS $0}
END {for (n in IN)
print...

... another option ...| cut -c10- | tr -d _

... could utilize awk, which natively handles floats:b=`echo $1|awk '{print $0*.43}'`

... my bad, missed the second page where this had been resolved ...

perl -ne '
if(m/User@Host/){s/\s//g; if($.>1){print "\n"}; print "$_ | "}
elsif((@m = m/\w+:\s\w+/g) && (0+@m>2)){print join(" | ",@m) }
else {chomp; print " | $_"}
' file