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I am getting error for all columns,in first column I have value 1 but still I am getting error..not sure what the problem is..

when i run below code in linux i am getting error for all columns.not sure why getting error in linux.please help me.

awk -F, '
NR==1{next}
{f=""}
$1!~/^[0-9]{0,12}$/{f=f?f"...

I am using below code to validate the source file,code working fine but if any column contains null value then below code throwing error actually it should not.how to customize the below code to...

When i pass parameter to sed command its throwing error as “SED cannot be parsed”.sed command is working if I pass directly.please tell me how to handle sed command with parameter.Please check below....

To convert file epcdic to ascill format,i am using below code.Getting some junk characters in output file.not sure what the issue is.Please correct if below command is wrong.

DD conv=ascii...

Sorry,i didnt mean it.

Below code is not working.


awk '/OCCURS .+ TIMES/ {n = $4; NF-=3; L=1}
/10 + FILLER/ {for (i=1;i<n;i++) for (j=1;j<=c;j++) print B[j]; L=c=0}
L ...

occurance will change from copy book to copybook but that will not be issue,help me to get 14 occurs itslef and always it will be 10 filler line only.

I have one mainframe copy book where I want to copy n times depend on occurs which mention below.
Example:
Below highlighted row mention “occurs 2 times” so I need to copy 2 times till next label...

Wheni run above command,i am getting result as below.i am not getting row.

Row:$0
Service ID have lesser precision
Row:$0
Service ID have lesser precision
Row:$0
Service ID have lesser...

i think above code will just print higher precision or lesser precision,i need a complete row which has higher precision.

I am using below code to find the length of first column additionally I want the complete row which length is greater than 12.at the end I want the rows where first column data length is greater...

In below third column it should accept any special characters,numbers,alphabets etc.it should check only length of the column, data can be anything.

$3!~/^[a-zA-Z0-9.%&@: -]{0,10}$/{f=f?f"...

Its working thanks for your help.

Geting syntax errror if i replace f with f=f?f" Error Code":"Error Code",can you please change in below code where i should replace f with f=f?f" Error Code":"Error Code".

awk -FÇ '...

Sorry i didnt get u,do i need to replace f as {f=" "} thats it?
awk -FÇ '
NR==1{next}
{f=" "}
$1!~/^[a-zA-Z0-9.%&@: -]{0,12}$/{f="ServicerID-error"} ...

I am using below code to validate whether datatype,length and date format is correct as defined in file_layout.
Below code is able to find only one error in a row,if there is more than one error in...