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That ^L is a pesky character. I've tried the above in sed and / or awk, used the octal \014 and the ^L, escaped it, quoted it, and everything else I could think to do, then directed it into a file...

When editing a file, vi displays a special character as ^L. Can you tell me the escaped character to be used in awk? And can that escaped character be used in a regexp in both sed and awk?

I want to match on pattern, print subsequent lines, then do NOT print from blahblah to EOF.
Pattern data data data
data data data
data data data
...
blabla <-- do not print to EOF. If first...

I would like it to stop after the data lines:
Pattern data data data
data data data
data data data
...
blahblahblah (another pattern match to stop printing?)

That sed command works great from command line, but when I put that pattern into an awk script, it only prints the pattern line. It does not print the subsequent lines. Can you tell me how to do...

Data:
Pattern Data Data Data
Data Data Data
Data Data Data
...

With awk, how do I print the pattern matching line, then the subsequent lines following the pattern matching...

I have a textfile which I am parsing with awk. The lines do not have the same number of fields, so sometimes $3 is the last field, sometimes not.

When I do a 'printf("%s, %s\n", $2, $3)', if $3...