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Finding very hard time to achieve this.
I have a text file extracted from XML file. The text file which is extracted is very large & has multiple blocks similar to the sample file given below

...

I have a XML file of little huge size. I have to build a logic to get the count of the tag <capacity>.

And have an if loop such that all the <capacity> blocks are captured one after the other.
...

@RudiC:

I had this doubt because it is not a good practise to use the curl output i.e in xml directly for processing or searching.
I tried converting that using lync and xmlparser but both...

I tried redirecting the output to a file and then opening that file. But still I face the same problem.

For your infornmation, when I run one by one as a command and then echo those variable in...

This is the file which contains only neccessary values from the output of curl command i.e TEMP_FILE

Proxy Hostname
server0123.domain.com
Proxy IP address
...

Thanks...!!! This was what I was looking for... But one problem here seems to be that it lists directory as well. I need only the filenames so I added an additional grep command with the code...

Unfortunately no.

In between I came across this piece of code in Google which seems to working fine in bash but not in ksh (ksh88)

find . -type f -mtime $(( ( $(date +%s) - $(date -d...

Thanks for your solution.

Unfortunately I dont have the required perl modules installed in my machine neither I do not have admin rights for that machine to install the required modules.

Kindly...

Not accessible to machine now. But I use AIX 6.1 OS machine with ksh88 version.

Hope this will be helpful.

Need a ksh script to get the files that were created or modified in a directory on a particular date entered by the user.

For example if a directory contains files as below :

> ll
total 41...

I use ksh88 version

I had tried this earlier but i was getting this error

ksh: 0403-057 Syntax error: `(' is not expected.

I have awk command :

awk -F ' ' '{ print $NF }' log filename

And it gives the output as below:


06:00:00
parameters:
SDS
(2)
no
no
no
no

doc=4000000000).


information:

@in2nix4life: Thanks for your suggestion...:), but when tried it out and echo con the result what i got is as below
$ echo $con
var1

@Don Cragun, MadeInGermany: It worked perfectly...:b: Thanks ...

Hi Guys,
I was scratching my head for this for half a day... finally not successful :confused:
Following is the problem

I have a variable
$ var1=123
$ var2-234
$ var3=345
and another...