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how can I pass multiple values from command line arguments

example
script.sh -arg1 op1 -arg2 op1 op2 op3

somehow I am not getting expected from this code also

Here is an awk program to remove last occurrence of pattern and from a file:

Code:
awk ' { a[++i]=$0 l = i; } END { ...

no trailing empty line in the output of $t

here is the command I am using.
echo $t| sed '$ s:and::'
here is the out from $t
on a.id1 = b.id1 and
on a.id2 = b.id2 and
on a.id3 = b.id3 and

Thanks

Thanks for your quick reply RudiC.But this command is removing all "and"s from each line.
I am getting out put like this.
on a.id1 = b.id1
on a.id2 = b.id2
on a.id3 = b.id3

Thanks

Hi all,
I am trying to delete last occurrence of word using sed command.
for example.
I have input like this
on a.id1 = b.id1 and
on a.id2 = b.id2 and
on a.id3 = b.id3 and
and I am expecting...