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Think I finally got it :) :) :)

Code in shell script

linedate="2/14/2013"
IFS="/" read mm dd yyyy <<EOF
$linedate
EOF
newvar=$(printf "%04d%02d%02d" $yyyy $mm $dd)
echo $newvar...

I'm still not getting this ... I'm not sure what IFS is .. The last set of instructions works, but what I really want is:

Read in data
field1 is everything up to first /
field2 is everything up...

Sorry ... when I say "native unix" I mean typing in the commands directly without using a script and executing the script. By the way ... I got this working with the following:
...

I thought that might be needed, I was trying to type it in native unix, so thought it might be needed to type on one line

---------- Post updated at 11:58 AM ---------- Previous update was at...

Trying to learn this on my own through trial and error, think it may be time to ask the big guns here ... will let you know .. thanks for your help ... This is not like Cobol :)

okay ... running

GNU bash, version 3.2.51(1)-release (x86_64-suse-linux-gnu)
Copyright (C) 2007 Free Software Foundation, Inc.


Please use code tags

I typed linedat="12/12/2013"| echo ${linedat:6:4}/${linedat:0:2} on the command line and all I got back was /

How do I tell what version of bash I'm using

Linux
/bin/bash

Told you I was new to this :)

Okay

Here is what I entered


linedate="12/21/2013"
lineyyyy=${linedate:6:4}
linemm=${linedate:0:2}
linedd=${linedate:3:2}
echo $linedate $lineyyyy/$linemm/$linedd


nothing is...

Hi ... extremely new to Unix scripting ... I have to get a date field from mm/dd/yyyy to yyyy/mm/dd format ... I have a variable that I want parsed. I don't seem to be doing it right?? Thanks.