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I got it! Thanks a lot

what if this 'input' isn't a file?
i have couple of numbers which is a result of a 'for loop'. assume that it looks like this :

for varN in 1 2 3 4; do echo $varN; done;
the result will be :
1...

hi..i would ask about how to write over data to new file with BASH.
so..assume my data looks like this :
11
12
13
14
15
...and so on. It's always line by line. and that's for the first file....

got it! Using 'read' that what i want.. Thank you very much for all of you. that's really helpful!

ya, i tried already that code. first, i dont really understand what 5 is. And to open or get the file, i just use $1.

would you mind reading my post where there's a 'grep' on it please :)
That's...

without using awk, maybe?

actually the data on file looks like this :

#there is some texts here
#also here
123 12 1234

and then i try to 'grep' those numbers with this :

grep -e '^[0-9]* [0-9]*$' $file | tr ' '...

what's the meaning of 1p or 2p?
what i know -n is for the line number, right?

thanks chabler_xl..
but, if i dont know the data at first. i mean, what i know is only.. there is a file with all data in one line like i write before. without knowing the first line is 123, second...

with loop? also with an array? i dont really get it. sorry

yes..that what i mean..

hi,..i'm beginner in bash.
my simple question is, how can i grep a line by line without using 'awk' maybe?
for example, assume i have a data like this :

123
12
1234

i would like to say...