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echo "$line"|awk 'x = 1;{for(i=1;i<=NF;i++) if ( $i ~ /[0-9]:[0-5][0-9]:[0-5 ][0-9]/){x = 0;print 1}}if ( x == 0){ print -1}'

This code is suppose to read a variable $line and return 1 if the...

Using the variable name as time was causing the problem.
Changed it to t and the the variable in quote fixed the problem.
Thanks you all folks

This the code for chkTimeFormat.sh is as follows
time=$1
var=$(echo "$time"|awk '{for(i=1;i<=NF;i++) if ( $i ~ /[0-2][0-9]:[0-5][0-9]:[0-5][0-9]/){print i}} ')

if [ $var -ge 0 ]
then
echo 1...

Thanks but ,
. chkTimeFormat.sh "$time"|read c

it did not work.
Any more ideas...

I have a shell program that calls another shell program

the following code works
. chkTimeFormat.sh "10/9/12 17:51:19:783."|read c

but when I am passing the the time in a variable like in...

I have a code like this


v_time=12:12:12
correctTimeFlag=$(echo $v_time|awk '{for(i=1;i<=NF;i++) if( $i ~ /[0-2][0-9
]:[0-5][0-9]:[0-5][0-9]/){print i}}')

if [ correctTimeFlag -gt 0 ]
then...

I have a code like this

v_num=9
comp_num=39
if [$v_num -gt $comp_num]
then
echo "pass"
fi
echo "end"

I am getting an error

ksh: [9: not found
end

When I change the code to ...

I have a variable
$line= Some text with ERR message

I want to get the value of the index of ERR and assign to a variable say $index

I expect the output
echo $index
16

I tried to use match...

How can I pass the date string pattern as variable
I am trying to run this in a shell script.
In the following way


awk -v x="11\/20\/12" '/x/,EOF{print $0}' datefiltertestfile.txt


This...

Is there a way with aw to print all lines after a string is found

There is a file like this

.......
........
2012/19/11 :11.58 PM some data
lne no date
2012/19/11 :11.59 PM some other data...

I need to print N lines before a pattern ERR-XXXXX .

The grep around and before option is not working for me.




input file
line 1 some text
line 2 some other text
line 3 ERR-12345
line...

myFunc(){
echo "In Function ...processing $1"

echo "awk '/\[$1/{sub("\\[","",$0);a=$0}/^ORA/{print a"-"$0}'"
awk '/\[$1/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' $2.log>>$3

awk...

the command is working in the shell.
However when calling this same command from a function
$0 is getting replaced by KSH and the date part is not coming only ERR part is coming

like this...

I have a file like this
-------------------------------
[2012-11-12 : 11:59
some text
some moe text
ERR-XXXXX
soe more text
]
[2012-11-12 : 12:00 blala blah blah]
[2012-11-12 : 12:01
...

rdrtx1, thanks for your suggestion , I checked , multiple environment (including those where mailx is working) there are no server informaton here..
There are 3 entries
broadcastclient
driftfile...

Hi ,
mailx is unable to send mail , I am getting the following error

Diagnostic-Code: SMTP; 553 5.1.8 <bc00644@dev-app01-wms.domain.fds>... Domain of sender address...

The modified script, couple of typos removed
awk '
{while(match($0,/ERR-[0-9]{5}/))
{
c[substr($0,RSTART,RLENGTH)]++ sub(/ERR-[0-9]{5}/,"")
}
} END
{for(i in c) print i "="...

Hi Bipinajith,

Thanks , for your prompt reply.
I am getting a message
grep: illegal option -- o

I am using ksh

The output without the -o option also seems to work, what are we trying to...

I am trying to search a file for a patterns ERR-[0-9][0-9][0-9][0-9][0-9] in a file and return a count for each of the error reported

Input file is a free flowing file without any format
...

It s working for a different user

I am getting the following error on sed command
This generating the following error

[2012-11-01 02:08:39,943 | ERROR | WebContainer : 3 | | MRF - Report UI] Print Requestor is not setup for user...

I am a newbie to shell scripting
I have a large log file , i need to work on the part of the log file for a particular date.

Is there a way to find the first occurance of the date string and last...