Search Results

Thanks RudiC, your solution worked for me and I have learnt 2 new function sub & gsub but I simplified it as per below command


echo '"Amit","Amit"' | awk -v COL=2 -v SRCH="Amit" -v REP="XXX"...

I wanted to search for a string and replace it with other string from nth column of a file which is comma seperated which I am able to do with below

# For Comma seperated file without quotes

...

Thanks Don :) , Solution is working fine but Need clarification for below

IAm=${0##*/} - I have understand that it is something like $0 but here we are removing leading string if it matches with...

Apologies for this, Will take care in future.

Please find the details

Operating System
uname -a
Linux XXXXXXXX 2.6.32-220.25.1.el6.x86_64 #1 SMP Tue Aug 14 13:14:38 EDT 2012 x86_64 x86_64...

Already given answer of Don Cragun's questions.

Make it generic means same code should work for any file where as file structure may differ and column number which need to drop may differ.

I just use cut command or awk to print the columns as mentioned by sam05121988 but I just thought of making it generic so that it should work for any file just we need to pass column number which we...

Thanks sam05121988 for replying.

But as I mentioned above I need generic solution which can be used for both input file as I can pass any column number to delete from file.

I hope I am...

I want to built a generic code to remove columns from file. Column number will be passed at run time.I may have multiple number like 2,5,10 so Can you please help.

I know how to remove when we...

Hi,

I have one script for which I want that other user should not read the script file but can execute. Is there any method ?

I tried by giving 711 but it gives Permission denied to other...

Thanks bakunin for superb explanation :) It really helped me to understand the each option used in command.

Thanks anbu23 and all for your inputs.It was really helpful.

I have input file as below I need to check for a pattern and if it is there in file then I need to print all the lines below BEGIN and END keyword. Could you please help me how to get this in AIX...

Please try this


sort file1.txt > tmp1
cut -d, -f1 file2.txt | sort | uniq > tmp
diff tmp tmp1 | grep '>' | sed -e 's/> //g' > file3.txt
rm -f tmp1 tmp

I wanted to sort the below data on 4th field(comma seperator) based on month and date and time on AIX OS.

Input data:

3,AJ,30 Jul 06:30,30 Jul 06:30
5,AJ,30 Jul 06:30,30 Jul 06:49
10,AJ,30...

I need the date format in YYYY.MM format and I am able to get current month date as well as previous month date with below command


PM=`date +'%Y.%m' -d 'last month'`
CM=`date +'%Y.%m' -d 'now'`...

Thanks vgersh99

It worked fine.

It would be very helpful if you can please explain what [._.] is doing and how it split 4th column into array and value assign to each array ?

I have tried below command but it is replacing complete string not specified pattern.
I am not sure how to check for sub string here so please help.


awk -F, '{ OFS="," ; if ($4 ~ /07/)...

I have posted this again as old post is closed and I am not able to reopen. so please consider this new post

Input File :


1,A,Completed,06.02_19.36,Jun 30 20:00
2,BBB,Failed,07.04_05.12,Jul...

$ cat /cygdrive/d/Final2.txt
1,A ,Completed, 07.03_23.01 ,Jun 30 20:00
2,BBB,Pending,,
3,CCCCC,Pending,,
4,DDDDD,Pending,,
5,E,Pending,,
6,FFFF,Pending,,
7,G,Pending,,


In the above file...