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awk '{
for (i=2;i<=NF;i++) {
n[i,$i]++
}
}

END {
for (i=2;i<=NF;i++) {
print n[i,1] " " n[i,2]
}
}' file

I don't understand. If you want to sort by filename why do you use -rt option (sorted by reverse time) and not a simple :
ls -l

or if you want only size + filename :
find ./ -maxdepth 1 -printf...

google : printf awk
first result : Printf Examples - The GNU Awk User's Guide (http://www.gnu.org/software/gawk/manual/html_node/Printf-Examples.html)

moreover a ">" delete the file and write the...

Is this homeworks ?

I think you can do it with awk ?
the 1)

awk '
/^.........patern/ {n+=1}
/^.....patern/ {m+=1}
end {print n ; print m}
' file 6 "." is for the patern in the 7th column.

maybe it's the newline between `` Try with a \

DESC=`/bin/awk -F',' "/^$JOBNAME/" \
/apps/test/scripts/library/desc.output.$AUTO`

You can use this sed:

sed '/line 1 pattern/{
N;
/\nline 2 pattern/ {
s/pattern/replace/
}
}' fileplease note when you use a "N" the pattern is in two line with \n separator. So you...

cat $ORATAB | grep ^+ASM | wc -l

please replace that by:
grep -c '^+ASM' $ORATAB

$# return the number of argument.

What is the line 23 ?

You forgot to add the numbers of the even lines. The code sould be :
sum[i]/2 ==> (sum[i] + $i)/2

something like that ?

awk '
$3 ~ /^longest_sequence/ {
if (x[$2] == 0) { print }
x[$2]++
}
' file > output

You can test it before asking if it could work!

arr[i] is the number of the i line. That mean if "i=4" arr[i^2] will return the 16th lines and not the square of the 4th line.

grep -w '"nathan available"'

for example :

awk '
BEGIN {sum=0;summ=0}
{
arr[NR]=$1
sum+=$1
}
END {
average=sum/NR

for (i=1;i<=NR;i++) {
summ+=(arr[i]-average)^2
}
print summ
}
' fileplease...

If you want to read a file 2 times :

awk '
FNR == NR {
first pass
next
}

{ second pass }
' file file

Easy (but you have to add a condition if you want to manage lines with only one field):
awk '{for (i=2;i<=NF;i++) {print $1 OFS $i}}' A.txt > B.txt

The problem is wc -l give the line number and the filename. So 2 solutions :

test=$(wc -l $X | awk '{print $1}')

OR

test=$(cat $X | wc -l)sorry.

awk '{ print $0 }' $X > “NR-${name}”

"NR" is a awk variable, the bash can't guess it ! If you copy a file with the number of lines you must use wc -l :
NR=$(wc -l $X)
cp $X $NR-${name}

file is the index (file2 in your example with "1 2 3 4 5 6 7").

awk '
function print_tab()
{
for (k=1;k<=j;k++) {
i=ind[k]
printf "%-4s",tab[i]
tab[i]="-"
}
printf "\n"...

If files are sorted and they don't have headers and the second field of file1 is never empty:
join -a 2 -e 'Not found in File1' -o 2.1,1.2 file1 file2
8734060356 2
8734079909 Not found in File1...

And what is this line 55?

It's a pretty good idea but you have to learn more about AWK:
echo 'a,b,c' | awk -F, '{$3 = "LTE" ; print $0 }'
=> a b LTESo if you wan to print only line with LTE in $3 there are a lot of...

Oups, simple quote has been removed by the copy/paste.

awk '{printf "s/" $1 "/& (" ; for (i=2;i<=NF-1;i++) { printf $i " "};printf $NF")/g\n"}' drugs.txt > file_sed