Search Results

but , they no repeat the loop while de condition its true ?

in this case a <= limite , so

if a = 1 do the first condition.

not do the second condition.

a++

out of while ,


the...

thank you very much but , i have a problem

the code now is


#!/bin/bash

limite=2
a=1

while [ "$a" -le "$limite" ]; # this is okay, no problem

do

if [ "$a" -eq "1" ];
...

#!/bin/bash

limite=3
a=0

while ["$a" -le "3"];
do


if ["$a" -eq "1"];
then

pru=/usr/bin/mei.txt
cat $pru | mail -s "IMEIS" mathias@wirtel.com.ar

fi

the systems return me

/usr/bin/imei: line 6: [: $a: integer expression expected
/usr/bin/imei: line 35: [: $a: integer expression expected


thanks and sorry , im newbie with this

#!/bin/bash

limite=3

while [ "$a=1" -le $limite ];
do



in the first while

but im not very sure of that

no , unix return me that errors


/usr/bin/imei: line 5: [: =1: integer expression expected
/usr/bin/imei: line 34: [: : integer expression expected

hello , what is wrong in this script ?
#!/bin/bash

limite=3

while [ "$a=1" -le $limite ];
do


if [ "$a" -eq 1 ];
then

pru=/usr/bin/mei.txt
cat $pru | mail -s "IMEIS"...