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here is the code i was trying

export ORACLE_HOME=/usr/local/opt/oracle/product/10.2.0
export PATH=${PATH}:${ORACLE_HOME}/bin

cat /dev/null > dsltn_sustaining
cat /dev/null >...

Hi,

I am trying to send an output of a script in an email.
I want to know if there is a way to modify the senders email not as my username on the host server but as one of the sender preset on...

ftp -in 00.00.0.0 <<E-O-F
user login password
type ascii
put file.txt
quit
E-O-F

will the above command need user name password?
the whole idea is the i want to avoid entering my secure id...

Hi,

Is there a way to transfer a file from one unix server from another without entering the login credentials. I know scp and other commands but it prompts the username/password.
However in my...

#!/usr/bin/ksh

id=`print $1 | sed 's/"//g'`
option=`print $2 | sed 's/"//g'`
shift 2
typeset -a server=( $* ) # capture remaining parms into the server list
total_server=${#server } # no...

Hi,

Below is starting entry of my script

#!/bin/ksh
Usage()
{
print "Usage: $0 ID OPTION SERVER"
print "<br>Where :"
print "<br>Enter your ID into PARAM1, OPTION in the PARAM2 and...

thanks for the insight. but i am still new to unix scripting.
NEWLIST=$NEWLIST" "SERVER_NAME
the above statement will be inside the for loop and will get append with new SERVER_NAME every time. ...

SERVERLIST="1:Server_1a 1:Server_1b 2:Server_2a 2:Server_2b 3:Server_3a 3:Server_3b 4:Server_4a 4:Server_4b"
RETURN_VALUE1=0


for VAR in `print $SERVERLIST`
do
SERVERNAME=`print $VAR | cut -d...

OLDLIST=$OLDLIST" "$VAR
are both OLDLIST and $OLDLIST going to be that variable?

i have a variable that has more than one value. i am declaring another variable, which will have the old variable data one by one. i want to use the second variable to hold the track of all the...