Search Results

I tried that exact code. The issue is that something is wrong with the use of "${file_delimiter}". when I echo the statement and exit the script, the value comes as an empty string. I'm not sure why....

cat ${landing_dir}/${lfile}|awk -F "${file_delimiter}" -v bad=${bad_file} -v good=${rootDir}/landing/Validation_EDITED/new_${lfile} -v fc=${file_field_count} '{if(NF!=fc) {print NR,$0 > bad;} else...

${lfile} is the file being parsed. Do I need to pass that as a variable as well?

I keep getting this error:

awk: (FILENAME=RESPONSE_2012.txt FNR=1) fatal: expression for `>' redirection has...

Thanks shamrock... I am still having an issue

I Changed code to awk -F ${file_delimiter} '{if(NF!=${file_field_count}) print NR, $0 > $bad_file; else
...

Hi All. Thanks for your help in advance.

I have a requirement to examine the number of delimiters in each record of a file. If the record has the expected number of delimiters it should be passed...