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Thanks for your help!

I wrote the day calculator also in bash. I would like to now, that is it good so?

#!/bin/bash

datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`

diff=$(($datum2-$datum1))
...

Is this code good for this purpose?

<?php
$date1 = mktime(0,0,0,01,01,1991);
$date2 = mktime(0,0,0,03,22,2012);

$diff = $date2 - $date1;
$days = $diff / (60*60*24);

echo ($days . "<br...