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I guess I don't understand what you are expecting in your output.
Let's step back and try to determine what you are expecting in your output.

Your sample output...

.
.
svn relocate cd...

Can't you change your query to spool only those records where the field equals what you are looking for?
I think that would be the easiest way.

Not knowing how you changed your loop. (Using original code provided)
I think this is what you want but this whole script is not very efficient..


for i in `cat ${wcfiles}`
do
...

Your echoing set values for your variables.
If you don't want to display OldRep and NewRepo if empty, you need to program for that.

Try this:

OldRepo=`grep svn01g.gdc ${i}/.svn/entries 2>/dev/null | tail -1 | tr -d '\n'`
NewRepo=`grep svn01g.gdc ${i}/.svn/entries 2>/dev/null| tail -1 | sed '/svn01g.gdc/...

Oops.
I didn't read the whole thing...

standard out (if any) will then show up in the crontab owners mail if I am not mistaken.

Sorry for stepping on you methyl. That was your discovery. I'll back off...

The character left of the 1 key.
Example:
OldRepo=`grep Oldhostname ${i}/.svn/entries | tail -1`

There was no confirmation from methyl's post about the missing backticks that assign the variables. Make sure this is not a typo.

Don't know why it wouldn't. What shell are you using?

echo "svn relocate " $OldRepo " " $NewRepo
echo "svn relocate ${OldRepo} ${NewRepo} " should work also.

Try updating this line.
OldRepo= grep Oldhostname ${i}/.svn/entries | tail -1to
OldRepo= grep Oldhostname ${i}/.svn/entries | tail -1 | tr -d '\n'