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DIR=$( ls -l | awk '{print $3}' )
will return the name of the owner for every item in the folder, while your solution returns the list of folders. They are pretty much the same, but if we want to...

@ahamed101:

A thank you is on it's way, but I think I got logged out from the site before I posted it, and now a moderator has to approve it. :-)

Your last code worked, just as it should be,...

WOW, thank you, that worked just perfectly!

I knew, it can be done very easily, I was just too amateur to find :-) it.

Well, I was thinking about getting a userlist with
cat /etc/passwd | grep /home | cut -d: -f1but this is messy too (extra results), and does not solve my problem. By generic I meant, that the...

Yes, like this, but my main problem is processing the folderlist in /home, because the script should work in any enviroment, not just with predefined names.

This:

cd /home
ls -l | awk '{print...

Hello, I'm trying to write a script which is listing files based on different preferences, like filetype or permissions. All is fine, except for one: I want to list files in /home which has a...