Search Results

mirko -
See my post #22 above.

So those ^M characters are your problem. Always use an editor like vi to create shell scripts, not a Windows editor like Notepad. To get rid of these, run:

tr -d '\r' < bashScriptTest.sh >...

I suspect you have DOS newline characters in your script which is causing it to behave incorrectly. Can you give the output of:
cat -vet bashScriptTest.sh

I was indeed mistaken. Thanks for putting me straight!

2 things are wrong -
1. You are missing a double quote in your expression (echo $VAR1")
2. Your test expression can't just be the output of the grep command - you need to perform some kind of test...

/usr/bin/sh on Solaris is plain Bourne shell, not bash. "[[" and "]]" will not work on this shell. You need to explicitly set a bash shell in your shebang or use "[" "]" for your test operator.

The error means that your shell does not recognise "[[" as a command, which means it is not a bash shell. Make sure the top line of your script is :

#!/bin/bash

echo <string> | sed "s/Cluster//"

#!/usr/bin/bash

for result in a b c d e f
do
echo "${result}=$(grep -c $result list.txt)"
done


Result:


a=3
b=0
c=2
d=2
e=1
f=1

This is not how grep works. By default, grep takes a file as its input. Your code is telling grep to look in a file named "for(i=1;i<=10;i++)", which obviously won't work.

Instead, echo the text...

echo "haighaihaihai" | grep -o "hai"

Maybe myprogram behaves differently if it is run from a different directory. Try running myprogram interactively from the command line using:

$HOME/here/lives/code/myprogram

Does it behave the...

The test is returning "too many arguments" because you have passed it too many arguments. This is an instance where you want to use backticks, because you need to pass the output of the grep command...

You should use them when you want to pass the output of what is within the quotes to another command, or a variable assignment.

e.g. if you wanted to assign the content of the user's passwd entry...

You need to remove the backticks as well:


if grep $username /etc/passwd > /dev/null

This will attempt to run the value of $username as a command, which is not what you want to do. You probably want to do



echo $username >> information_file



You should also validate...

Make sure your script contains only Unix-style end-of-line characters.

cat -vet main1.sh

You should only see


#!/bin/sh$
while read DAYS INDIR OUTDIR$
do$
find $INDIR -type f "!" -mtime...

1. You are using a numeric comparision operator (-eq) to compare strings.
2. Why don't you test for inequality instead of equality?
3. You are missing whitespace between your test arguments and...

You have 2 issues here:
1. Your data is delimited by the "|" character so you need to specify this to awk with the -F argument:
awk -F "|" '{ if ( $2 > 50 || $3 > 50 || $4 > 50 || $5 > 50 ) print...

OK, so I suspect the file is not in plain text format or doesn't contain any valid newline characters. Excel might have exported it in the wrong format.

Try the following

tr "\r" "\n" <...

That works fine for me

$ awk '{ print $3 }' xl.txt | more
161
PGP_JFY63
COC084
Addicts
M
42
-0.785714286
-0.785714286
-0.785714286
-0.785714286
-0.785714286
-0.785714286
2.214285714...

Can you give some sample lines from the text file?