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OK, thanks, it explains the problem. Solved it by just substituting with sed:

$ echo "2.5" | sed 's/\./,/' | awk '{temp = $1 - 1; printf("%f\n", temp)}'
1,500000

That's enough for my needs in...

Wow, that was fast... :)

However doesn't work on my Mac with its awk

$ echo "2.5" | awk '{temp = $1 - 1; printf("%f\n", temp)}'
1,000000

$ awk --version
awk version 20070501


any other...

Can someone explain whats happening here:

$ awk 'BEGIN {print (2.5 - 1)}'
1,5


2.5 - 1 is correctly calculated to 1,5 (using european locale)

$ echo "2.5" | awk '{temp = $1 - 1; print...