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Is it possible to dry run a php script without actually executing it? Say I need to test the output of a php file to see if it matches a pattern. I need to run this on all php files on the server....

Extract of configuration file.

members server1.domain1.com,server2.domain2.com,server3.domain3.com

I am writing a script to remove the server members from a conf file. When I run the...

I need to change a pattern with single quotes


# echo "serversignature: 'On'"
serversignature: 'On'


I did

# echo "serversignature: 'On'" | sed 's/.*serversignature.*/serversignature:...

Thanks a lot. It worked.

I need to get the port numbers only from these list.


127.0.0.1:53
0.0.0.0:25
127.0.0.1:953
:::62378
:::47353


Ie print fully from right when the pattern : is matched. The ouput should be...

11
22
33
44
55
66
77


When pattern 55 is met, print upto it, so output is


11
22
33
44

Yes you are right. The one you gave works flawlessly.

This worked


# grep username /etc/passwd | sed 's/\/bin\/bash/\/sbin\/nologin/'
username:x:32008:32011::/home/user:/sbin/nologin


---------- Post updated 11-19-11 at 12:01 AM ----------...

It comes as follows.

user:x:32008:32011::/home/user:/bin/bash:/usr/local/my/bin/noshell

I have a pattern

username:x:32005:32006::/usr/local/user:/bin/bash

I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell

So it becomes
...

I need this.

aaa
OOOOO
bbb
ccc
OOOOO
ddd
fff
ggg
OOOOO
iii
OOOOO


I need all OOOOO replaced with PPPPP, but only change after the pattern ggg. So the first two OOOOO should not be...

I got it corrected. If the count is more than 3, it will display it.


hour=`date | awk {'print $4'} | cut -d: -f 1`;lasthour=`expr $hour - 01`; lasthour=`printf %02d $lasthour`;grep "`date -I`...

I am trying manipulate variables inside a variable

root@server [~]# hour=`date | awk {'print $4'} | cut -d: -f 1`;lasthour=`expr $hour - 01`; lasthour=`printf %02d $lasthour`;grep "`date -I`...

thanks it worked

I need help on arithmetic

root@server [~]# hour=`date | awk {'print $4'} | cut -d: -f 1`; echo $hour
04
Now I subtract this result by 1 or 01 I get "3" as the answer. I need "03" as the answer,...

The below gives the nameserver details from the zone file. I need the nameservers registered for a domain at the registrar. Should be able to get from command line. The value in the zone file can be...

I get the following error:

# nslookup -qt=any domain.com
*** Invalid option: qt=any

I am looking for a free whois lookup tool or some "scripting help" that will give uniform result for whois lookup from the linux command line.

Currently:
whois of a .co.nz domain results...

I have in a file

domain.com. 1909 IN A 1.22.33.44
domain.com. 1909 IN A 22.33.44.55
ns1.domain.com. 1699 IN A 33.44.55.66
ns2.domain.com. 1806 IN A 77.77.66.66


I need to "grep" or "awk"...

I try below

server 1# cat file1
aaa
bbb

server 1# cat file2
ccc
ddd

server 1# cat test.sh
#!/bin/bash
var=`paste file1 file2`
echo $var

server 1 # sh test.sh
aaa ccc bbb ddd

...

I have file1 contents as

aaa
bbb
ccc


file2 contents as

ddd
eee
fff


I need to write for loop with two variables, so that I get the output as follows.
I have a third file that...

Thanks xbin, your second code worked fine. :)

I wrote this script


#!/bin/bash

var=`du -sch /var/log/messages;du -sch /var/log/maillog`
echo $var


I am getting result as follows.

# sh my.sh
2.1M /var/log/messages 2.1M total 296K...

I use the following shell script in bash and it works fine. It returns 1


[root@server ]# cat /etc/httpd/conf/res.txt
maldet(24444): {scan} scan completed on eicar_com.zip: files 1, malware hits...

Thanks a ton it worked :b: