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You can use ls -lrt|tail -1

Hi All,

I'm bit confused with a script
Any help would be appreciated

I have a config file say config.cfg and iam loading config file in My_Script.sh..The script name is My_Script.sh....

Thanks Corona688 (https://www.unix.com/members/43551.html) and apmcd47 (https://www.unix.com/members/302091426.html).. Both worked...

Hi corona
In .csv file the columns are comma seperated and so am getting different output rather than what i'm expected.
Can u help me in this

---------- Post updated at 08:43 AM ----------...

Are they really all in the same order like that?

yes.they are in same order...

Thanks :)...I'll try this.

Hi experts,
please help for my script..I'm confused how to do this.

i have 3 .csv file(excel file)
The 5 .csv files are

A.csv,B.csv,C.csv

A.csv has

column1 column2
a...

Thank you so much..it worked for me...

Hi Hergp
Thanks for the reply

ls -lrt file-2011030[1-5]*.gz

This command works fine for dates 1 to 5.But if I want to list files from 5 to 15 then how to list..

Hi ..I need help with unix ls command..
i have a list of huge files with file names like
file-2011030100.gz
file-2011030101.gz
file-2011030102.gz
...
...
file-2011030123.gz
...