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Merry Christmas! With a few improvements after @Franklin52:
awk 'BEGIN{RS=">"}NR>1{sub("\n","\t"); gsub("\n",""); print RS$0}' file

You could try using a tab, instead of replacing the new line with nothing:
awk 'BEGIN{RS=">"}{gsub("\n","\t",$0); print ">"$0}' file

try this:
awk 'BEGIN{RS=">"}{gsub("\n","",$0); print ">"$0}' file

I don't believe you can overwrite the original file without causing a problem. Although this did work for me:

{print > FILENAME}But to be safe, you can move the new file to the old file after awk...

If I understand you correctly, you want to specify the value to insert after DRIVES. Try this:

z="TEST"
grep -l '0007862454' ./* | xargs awk -v newDrive=$z '/DRIVES/{a=NR+1}...

Try this from within the directory your files are in:
grep -l '0007862454' ./* | xargs awk '/DRIVES/{a=NR+1} a==NR{$0=FILENAME}{print > FILENAME".new"}'

Perhaps an over simplified solution:
ls | awk '{printf "%s.%05d\n", $0, i++}'

If vbe is correct you should be able to clean the file using the dos2unix utility:

dos2unix hello.ksh

Then try running your script.

Alternatively, as you initially thought, sed proves more concise:
sed '/^PC/{N;/\nPC/!{s/\n//};P;D}' file

try this:
awk '/^PC/{a[NR]=$0}!/^PC/{a[NR-1]=a[NR-1]$0}END{for(i=0;i<NR;i++){print a[i]}}' file

awk '/0/' file

If you use awk instead of grep then you can set $1 into a local variable:

new_var=$(awk '!/Col1/ && !/-/ && $5=="Y"{print $1}' my_test.log)

Unless I misunderstand you, there is no problem with committing directory trees into source control systems. If you want a structure of /mod1/files then you should just create it on your local file...

I read the other day, a better way to do this:
ps -ax | grep [f]tpd

If you want to test your amount and then print the formatted line if it passes the test, try:


awk '{a=substr($0,33,11); line=substr($0,1,1) "," substr($0,2,19); if(a>712.40) print line}' file
...

This is perhaps overkill, but this will handle files of different dates...

In the directory with your files:
ls *csv | awk -f matcher.awk
where matcher.awk contains:


BEGIN{FS="_"}
{
...

how about just piping the grep output into the awk command?
grep -A1000000 "Acceptance" Brown_DL | awk '
NR==1
NR>1{ for (i=1; i<=NF; i++) { a[i]+=$i; }}
END { if (NR > 1) { for...

awk -F"\x01" '{for(i=1;i<NF;i++) if($i=="TAG001")print $(i+1)}' file

try this from within your folder with the links:
find . -type l | xargs ls -l | awk '{system("ln -sf " $11" "$9)}'

Although, you may want to test this first or it will mess up your links:
find ....

I'm not familiar with nawk, but shouldn't the toupper be done before the print?
if(/^cn:/) x=toupper($0); print NF?$0:a[x]"\n"Also, I just noticed this:
but in your example:
id_list
cn: abc, id:...

I think your file must have some control characters in it that are not visible and also not copied into your example text.
That would explain why the code works when I use it on the examples given....

No problem. It is better to make the code more readable:

awk '
/UDP flood/{ --> match lines with UDP flood
flood=$0; --> copy it for later
if(line){ ...

try this:

awk '/UDP flood/{flood=$0; if(line){print line ORS $0;line=""}} !/UDP flood/{line=$0; if(flood){print flood ORS $0;flood=""}}' file

awk -F= '/MSISDN/{s=(s=="")?$2:s"+"$2}/SMSMSG/{s=s"="$2;print s;s=""}' file

grep -E '/\*.*\*/|\-\-' file
or if you have multi-line /* */ comments:
awk '/\/\*.*\*\// || /\/\*/,/\*\//{print}/--/' file