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I really like this one :b:

sed 's:<a href="\(.*\)">.*</a>:\1:' url_file

Sorry for misunderstanding you. Try this :
grep -v "UDP flood" -A1 filename | grep -vE '^--$'

grep -An print n lines After the line found by grep
grep -Bn print n lines Before the line found by grep
grep -Cn print n lines of Context from the line found by grep (n before and n after)

I'm sorry but your script and your questions are a little difficult to understand :/
Furthermore I don't have access to your oracle database to reproduce your test (We don't know what's inside your...

I should have read a little more attentively ... You could try this:
su - oracle -c "$(eval echo "exp user/pass@localdb file=/oracle/oradata/backup/exp_cal_hist_$var1_$var2_`date...

You misunderstood this line. It runs what's between do and done, as long as $n is lower or equal than the first argument (i.e. $1) of the script.

$1 and $2 are arguments for your script. How do you call your script ?

Could this help you ?
TZ=GMT date -d '20010101 01:01:01 -0102'It takes the date 20010101 01:01:01 and ADD 1 hour and 2 minutes. It's more a hack but it can be used for simple date manipulation.

It could be better with not using the export command:
# TZ=GMT date
Tue Apr 5 13:34:27 GMT 2011
# TZ=GMT+1 date
Tue Apr 5 12:34:35 GMT 2011
# TZ=GMT-1 date
Tue Apr 5 14:34:38 GMT 2011

I'm...

curl <url>

Try this one when sending your mail:
( echo "${message}"; eval ${attachmentString} ) | mailx -s "${subject}" "${email}"

Use ';' instead of ',' in your csv file. In your locale the comma is the decimal separator and Excel can't use it as a field separator.

Try this:
date +'%d %b %Y %H:%M:%S' -d "$year$month$day $hour:$min:$sec"

Is this sufficient ?
ll file*110328Z

Try this:
tr '\n' ' ' < filename | sed -e 's/;/;\n/g' -e 's/[[:blank:]][[:blank:]]*/ /g'

You're right, that why I said untested ;), I usually test my scripts before posting but this time I was in an hurry

Here is an untested solution:

for file $(ls Folder1)
do
ls Folder2/$file Folder3/$file* 1>/dev/null 2>&1
[ $? -eq 0 ] || cp Folder1/$file Folder2/$file
done

getopts stop analyzing the arguments at the first one it doesn't recognize, so you need to give him only the optional arguments. This can be done with a shift.


arg1=$1
arg2=$2
shift 2
while...

if A1 is alone on the line you can use grep "^A1$"if A1 may be mixed with other data grep -w "A1"

This should do the trick in one grep command
word="posted"
grep -E "^[^:]*[02468]:.*${word}$" yourfile.txt
But as Franklin52 stated, if this is part of an home assignment you should have posted it...

Did you even try ? wget ****.com/content.php?file=movie.wmv

The error may come from your actual code and not the code you included.
Please post the complete code (specifically around line 43)

A little enchancement of cero's bashscript
#!/bin/bash
wc -w Article*.txt | head -n-1 | while read WORDS FILE
do
[ $WORDS -le 400 ] && mv $FILE /path/to/new/folder
done
The script will not...

If you have a single space in your empty lines, your command won't work.
grep -v "^[[:blank:]]*$" filename > newfilename will remove lines with only blank characters