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Sorry for leaving that out methyl, it's Solaris Sparc 5.10.

The server I've been testing on has logs that were copied over and all have the same modified date. I just discovered that only some...

I'm on Solaris (said that in the first post). I don't know much about the hardware other than it's on slower disks than production. I can find out more if needed. It takes about 7-8 minutes for one...

Jim - I got this error:
% 10 : syntax error
Rdc - Thanks that worked this time, although it runs in the same amount of time as the other solution

Chubler - Thanks, but we don't have that...

Thanks for your responses!

rdcwayx - I got the same error:
/usr/bin/ls: arg list too long

methyl - I got this to work, however it runs very slow. Is there a way this would work as a one liner...

Hello,

I'm trying to search through 30,000 files in 1 directory, and am getting the "arg list too long" error. I've searched this forum and have been playing around with xargs and can't get that...

I was able to find someone to help me on this. The correct code is:

perl -ne '/USERID:\s"(.+?)"/ ? print "$1\n" : print "\n"' datafile.log > userid.log

So I ran my script with the suggested perl statement inside the while loop, and even though it completed successfully, it took over 6 hours to run reading line by line in a 90MB log file. I've...

I ended up using what pludi suggested and it works perfectly. Thanks for your help!

cat $<logfile> | while read a
do
userid=`echo $a | perl -ne '/USERID:\s"(.+?)"/; print $1, "\n"'`
#do more...

I should have added that I'm going to be doing this for about 10 different strings per line. The code I have so far is:
cat $<logfile> | while read a
do
variable1=`echo $a | grep "USERID:" ???? `...

Hello everyone,

I'm a newbie here. I'm working on a ksh script on Solaris 5.10 and have a question. I'm trying to search for a word line by line in a log file, and grab the text right after it...