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Try this following:


flag=0;
while read line;
do

if [[ $flag -eq 1 ]];
then
echo $line | grep -qv "stop"
if [[ $? -eq 0 ]];
then
...

Please give the error you're seeing in console. It will be useful to understand the issue rather reading ur script code.

ksh not found means, ksh shell is not available for execution. What is the first line in the script (seabang operator like #!). Check whether that binary is available else use available shell binary...

Try this.


[muthuk@nexthallwhen-dx tmp]$ cat file.txt
qq ww rr tt ee ff
qq ww rr tt ee ff
[muthuk@nexthallwhen-dx tmp]$ cat file1.txt
aa
aa
[muthuk@nexthallwhen-dx tmp]$...

Try the following:


print "\nPlease enter your name and marks :";

open (OUTFILE, ">>report");

$name = <STDIN>;
$mark = <STDIN>;
chomp ($name);
chomp ($mark);
print OUTFILE
$abc =...

Second cut delimiter column # is wrongly put as 5 instead of 2.

get_input_file()
{
FILE=$1
echo $FILE
TYPE=`echo $FILE | cut -d "_" -f 3`
echo "Type is $TYPE"
EXTN=`echo $FILE | cut -d "."...

Extend the working version of your command of

echo `grep -i ${name} ${FILENAME} | sort -t'_' -k2,2 -n | tail -1`

echo `grep -i ${name} ${FILENAME} | sort -t'_' -k2,2 -n | tail -1 | awk '{...