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Is there a way to find out put from double echo something like below

var=`echo `echo $I``

$I containes the $ and second echo should display the actual path , Any examples ?

$PATH1 and $PATH2 are visible for all users or environment variables set in the .proifile

$cat FILE.txt

$PATH1/file1.txt
$PATH2/file2.txt

where$PATH 1 = /root/FILE_DR/file1.txt
$PATH 2 = /root/FILE_DR/file2.txt
for I in `cat FILE.txt`

do
v=`echo $I`

echo $v


if [...

$ ls -lrt file*
-rw-r--r-- 1 08:53 file1.txt
-rw-r--r-- 1 08:54 file3.txt
-rw-r--r-- 1 10:50 file2.txt

$ awk '/FIRST/ && !/SECOND/ {print FILENAME}' file*
file1.txt
file2.txt
$ cat...

$ ls -lrt file*
-rw-r--r-- 1 08:53 file1.txt
-rw-r--r-- 1 08:54 file3.txt
-rw-r--r-- 1 10:50 file2.txt

$ awk '/FIRST/ && !/SECOND/ {print FILENAME}' file*
file1.txt
file2.txt
$ cat...

there can be n number of files , just giving Direcotry not giving file names,

Also when -v is given it will find in the current line only not in the entire file.

need to find all files in the...

tried

find . -type f |awk '/FIRST/ && !/SECOND/ {print FILENAME}'

did not work.

I have 3 files in directory X, below are the files and its contents.

ls -lrt

File1.txt
File2.txt
File3.txt


>cat File1.txt

dfgjhf fjd FIRST

>cat File2.txt

dfgjhf fjd SECOND FIRST...

I have a file which has below data, i need to replace all new line characters within the quotes only,please help?

"Data"|"Data2"
"Data"|"Data
2"
"Data"|"Data2"
"Data"|"Data2"
"Data"|"Data
2"...

What is a hard and soft match in unix profiler ???