Search Results

i was trying that but was told not to create any files. So now i put the output in a variable.
I tried this code using Devtakh's idea & it worked:

for v in ${var1}
do
first=$( echo $v | cut...

the issue is m a beginner to shell scripting. dont know the exact commands. would appreciate if some one cud post a script for it

yes I can do that as well, but whats the logic of filtering? cause All i want from that is the file paths. but it also displays other information like the release label & objects:

Hi durden,
The output files cud be anything like .mp, .ksh, .dml. What I was thinking is I will put the output of the first command to a variable. so everything is in a string format...

Hi people,
I am writing a korn shell script, and one of the command gives an output something like below:

release.label.2010.03.02
objects:
/project/path/to/some/file_name.ksh...