Search Results

try this...

awk '{if ( $0 != "") print $0 "/alpha.jpg"}' file

y dont u try ..
ls -a *.edf > output

try out...
$ echo "Status: 0000" | egrep "\bStatus: *([0]+)";
Status: 0000

gives me the correct output..as proposed by scott above....

sed -ne '/not found/p' fileA >> fileB

If you want to do it thru ur perl script one of the following methods may work :

1) system("grep "PANIC" test.out > /tmp/PANIC");
2) `grep "PANIC" test.out > /tmp/PANIC`

sed -e 'a\
\
' fileA >> fileB

Try this out..

try this


sed -e 's/\<Virtualhost[^$]+\<\/VirtualHost\>//g' /tmp/test


Use code tags please, ty.

oops...plzz chng it to

echo $PARAM|sed -e 's/(\d+)\/(\d+)\/(\d+)/$3$2$1/g'
:o

you may try something like this :

sed -e 's/(\d+)\/(\d+)\/(\d+)/$3$2$1/g' | echo $PARAM

It has been assumed here that the date value is retrieved in the parameter PARAM

Hi All,
I need to first of all establish a connection to remote unix server non-interactively with the help of a shell script and then connect to oracle database from that server all with this...