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It has to be beer/real ale for me. Good ol' English pint of bitter, delicious!

Your a star!

Seriously, I was trying to make it too complicated. All it took was 20-odd lines. I modified it to suit my situation and it works an absolute treat.

Cheers,
Adzi

Thanks for the replies. The CSV file is ordered by day and month now, listed as such...
name,telNo,birthday
test 1,123456789,1989/01/26
test 2,123456789,1986/01/27
test 3,123456789,1989/06/09...

How do I check if the out put is null?

I'm used to other languages such as VB etc so a logical port for me would be to do
if
$variable is null then
$date + 1
fi
However I'm pretty sure...

1. The problem statement, all variables and given/known data:
Display from a csv file, birthdays that occur today. If there are no birthdays today, the next one in the year.


2. Relevant...

I kept trying it and trying it and in my sleep deprived state I realised it was commented out... oopsy :$

Many Thanks,
Adzi

Hi,

Edit: The title should really read listing files in a non-parent directory, sorry!

Im trying to get one of my Bash scripting assignments done for uni and now I'm stuck. This is probably...