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Thanks man for the details ...I had understand now.

:b::b::b:

another approach:-

nawk 'a[$3$4]++ { $3 -= 0.1}1' test

but kindly radoulov in your solution
awk '($3 -= 0.1 * c[$3,$4]++)||1' infile

why you used multiplication instead of
awk '($3 -=...

radoulov in your code below kindly what is the "x" for?



awk '$0~"^"(NR==1?"\"":x "http:")&&$0=RS$0RS' RS=\"

Hay:):):) thanks radoulov both codes working great..regarding perl my machine is customized & I am not the owner of it just simple user.

:D:D:D:b::b::b::b:

Scrutinizer it is not working:-

bash-3.00$ echo '"http://a.b.c" blablabla "http://b.b.f"' | sed 's|\"http://[^\"]*\"|&\n|' | sed -n 's|.*\("http://[^"]*"\).*|\1|p'

o/p
"http://b.b.f"

...

ok thanks man
:b::):):):)

---------- Post updated at 04:31 AM ---------- Previous update was at 04:30 AM ----------

but how can I achieve this using sed or awk. it still not direct reach....

-o option is not supported in grep command in my OS "SUN Solaries".

Scrutinizer you are wrong because see below:-
Iam using SunOS server2 5.10 Generic_118833-36 sun4u sparc SUNW,Netra-210


bash-3.00$ echo '"http://abc" blablabla "http://cvd"' | grep...

You may use egrep or grep as well and result here will be the same.

egrep ""http//.*""
or
egrep "\"http//.*\""
or
egrep '"http//.*"'



:D:p:D:):D

you can use gawk as well it is easy using it.

gawk '(substr($0,9,9)=="mueller02") {print}' file.txt