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When I loose the quotes..
The terminal says, Unary operator expected.

Ok.. thanks Decent and Methyl for letting me know about backticks.

Here's my updated program:
echo Enter a number
read no
i=1
ans=0
while [ "$i" -le "$(expr $no / 2)" ]
do
if [...

what??
excuse me.. I didn't get you..

Ok..
I fixed it..
Also fixed in
if [ 'expr $no % $i' -eq 0 ]

But still some problem!! :(

Here's my work of testing whether a number input is perfect or not..

echo Enter a number
read no
i=1
ans=0
while [ $i -le 'expr $no / 2' ]
do
if [ 'expr $no % $i' -eq 0 ]
...

I don't know how to delete this thread.
Admin/Mod, Please delete this thread.

Thanks.