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pls be specific ...


mv abc123456 x123456

can you please put in the command u used...
as i'm not getting any error wen i use it...

try this:

am sorry about the syntax i gav...

sed 's:[0-1][0-9]/[0-3][0-9]/[0-9][0-9][0-9][0-9]:10/18/2009:g' file_name

sed 's:[0-1][0-9]/[0-3][0-9]/[0-9][0-9][0-9][0-9]:10/18/2009' file_name

Try this...

One way of doing this:

awk '{a[FNR]=a[FNR]" "$0} END{for(x in a) { print a[x]}}' file1 file2 file3


Panyam has given a good option... i never knew this thanks ...

did u try using "ls -lad" ??

hi..

let f10=""

if [[ -z $f10 ]]
then
echo blank
else
echo non-blank
fi

this will work...

resetting the value of "i" to zero(0) did not happen... that is why it prints all the lines between regular expression...

sed -n `grep -n <reg_pattern> <filename> | head -2 | cut -d":" -f1`,`wc -l <filename> | cut -d" " -f1`p <filename>

This is for your satisfaction,.... this would work fine but not recommended......

Any idea how to make files/folders password protected...
I dont want to change the permissions of the files/folders...

that was good reply vgersh...i never knew this...thanks...

hi Praveen for the time being declare a variable
#!/usr/bin/env bash
# Bash_script001.sh

echo " Inside Bash_script001.sh";
s="$"
...
...
...

cat>>"Bash_script002.sh"<<EOF...

thx for pointing out ripat...
the following code will work fine:

awk -F":" 'NR==FNR{a[$1]=$0; next} NR!=FNR{if(a[$1])print a[$1]; else print $0}' shadow2 shadow1...

@ Praveen:

so is it working fine now ??

hi vi...

wen your replied
" Is it possible you left out the ; before the else? That would give a syntax error."

i have already posted two codes and i couldnt fig out which one u were...

the output which got:

awk -F":" 'NR==FNR{a[$1]=$2; next} NR!=FNR{if(a[$1])print $1," ",a[$1]; else print $0}' shadow2 shadow1
David $1$FbP0lc8N$MIJ8outnkYyBedIYK7TJ6.
sarvani ...

hi vi,

awk -F":" 'NR==FNR{a[$1]=$2; next} NR!=FNR{if(a[$1])print $1," ",a[$1]; else print $0 }' file2 file1

which semicolon you are pointing to...i dint get you ???
i hav executed this...

am sorry i dint get the error...
can you please give the complete error...
for the time being can you just try the following code

awk -F":" 'NR==FNR{a[$1]=$2; next} NR!=FNR{if(a[$1])print $1,"...

my understanding about ur requirement is ...you are looking up the value from password file and matching with it on a different column...

awk -F":" 'NR==FNR{a[$1]=$2; next} NR!=FNR{if(a[$1])print...

Hi Revathy,
"binlib" has given an excelent code... just modifyin his code will get you your desired result:

code:
sort -k2,5 -k19,19r -k1r filename |sort -mu -k2,5

kindly try this one and...

Hi Gross... as Our friend franklin has mentioned the code will work perfectly fine...
just adding to it...handled few other conditions too...
sed 's/,/| /g' file | awk '{print $0","$(NF-1)","$NF}'...

Check the size of the filesystem...
This might give you a vague report saying the file system has so much contents... and putting in contents means this has been used very frequently... so we can...

Hi sam:

My understanding on your question is
you want to display the 4th column in that file if that was your ques then

awk '{print $4}' <filename>

the above code will work...
am...