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One way:


#!/bin/bash

file1=$(date '+%Y%m%d')
file2=$(date -d "1 day ago" '+%Y%m%d')
file1=$file1"_file.txt"
file2=$file2"_file.txt"
diff $file1 $file2

You are not passing any array, just a string is being passed and thats why the error.

Try like this:



test1(i,"A"i,"B"i+1);
split("hi:aa:ab",c,":");
...

You cannot give the source file directly. Compile your C program and get an exe, and then execute the exe from the shell script.

Like:
Compile your C program:

$ cc -o myprog main.c
$ ls...

To make your aliases work inside shell script, add a line like this in the beginning of your shell script:

source .bashrc #Assuming your shell is bash and rc file is .bashrc

Guru.

One reason could be, you need to escape the asterisk:

xyz=$(echo $ln/$val1\*100-100|bc -l|xargs printf "%1.0f\n")

Guru.

For zero padding in ksh, use the typeset command:

$ typeset -RZ5 x
$ x=25
$ echo $x
00025

Mapping it to your case:
$ length=15
$ value="1234567890"
$ typeset -RZ${length} value
$ echo...

Like this since you are in Linux:

$ cat file
roses are red, so what do i do
nothing, just get the next string


$ var=$(grep -oP '(?<=roses )\S+' file)
$ echo $var
are

Guru.

rc file gets sourced whenever user gets into a sub-shell, and hence the aliases gets reflected in sub-shell. This is not the case for shell script. To get the aliases inside the shell script, you...

You can do it like this:

printf "%15s\n" "$value"


For dynamic:
printf "%*s\n" $length "$value"

Guru.

Assuming the space before the 2nd column in the input file(line 1) is a typo:

awk -F, '{x=$4;$4-=a[$1$2];a[$1$2]=x;}1' OFS=, file

If not a typo, use this:
awk -F, '{gsub(/^...

If your grep is GNU, just grep is enough:

To get the Head:
$ grep -oP '(?<=Head=")[^"]*' file
Test

To get the Title:
$ grep -oP '(?<=Title=")[^"]*' file
mode

Guru.

It's very hard to understand what you are exactly trying to ask. Can you please re-phrase your question better?

Guru.

Sort the files and compare:

diff <(sort a) <(sort b)

Guru.

One way:
sed 's/.*32=\([0-9]*\).*/\1/' file

Guru.

Like this:

my $version = "MYSQlcl-5.2.4-264.x86_64";
my @array1=$version=~/\d+/g;
my @array2 = (5,3,2,112);
my $ver1=join '',@array1[0..3];
my $ver2=join '',@array2;
if ($ver1 == $ver2){
...

It is actually checking whether the variabe _TABLESPACE_OFFLINE is empty or not.

If you are ok with a Perl solution:

$ cat file
abc 10.122.53
10.122.53.5
efg 25.a23.33.44
12.176.254.24

Perl command:
$ perl -i -ple 'if...

One way:

awk '/^[^>]/{printf $0;next}NR!=1{print "";}' file

Guru.

One way:
find . -type d -exec du -s '{}' \; | awk '$1>100{print $2}'

@Pikk45:
Your solution is relying on the size shown by the ls -l output which actually is the block size for a directory....

sed -n 's/.*bhaski.\{4\}\(.*\)/\1/p' file

Guru

sed is ideal for these kind of things:

echo $line | sed 's/.*TYPE ="\([^"]*\)".*/\1/'

Guru.

One way:

awk '{sub(/CP/,"CP\n");}1' file

Guru.

Assuming your files are f1 and f2:

To print lines present in both the files:
comm -12 <(sort -u f1) <(sort -u f2)

To print lines present in f1, but not present in f2:
comm -23 <(sort -u f1)...

You can replace your whole code with one awk statement:

awk -F, 'NF>3{print "Error at line "NR;exit}' $TEMP_FILE

In place of 3, put the count of your no. of expected fields.

Guru.

sed -n '/SOURCE.* NAME /s/.* NAME ="\([^"]*_SRC\)".*/SOURCE->\1/p' file

Guru.