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How to check out apache is installed in unix box ?

i don't have execute for httpd -v command and also i don't have 'apache' directory under /usr/local but i could able to see many httpd processes...

awk '(NR != 1 && NR != 2) {print $0}' < filename> , it should be &&

If you don't use nohup , whatever output is being generated by the script you executed will be thrown to your terminal that will disturb your work when you do something in the prompt. So, It is...

find . -type d -mtime +4 -exec rm -rf {} \;

For more infos : Unix find command helper (http://find.unixpin.com)

1 Processes ordered by cpu usage :

ps -eo pcpu,pmem,args | sort -k 1 –nr | more

2 Processes ordered by memory usage :

ps -eo pcpu,pmem,args | sort -k 2 -n

chmod 2710 <filename>

Try this.

cat filename | paste - - - -

Try this.

Try this

comm -13 a1 a2 | sed '/^$/ d'

You can find some CPU infos in "machinfo" command

This may be simple and will work if you have only two "WARNING" keywords in the file

#!/usr/bin/sh
start=`grep -n WARNING file1 | cut -d":" -f1 |head -1`
end=`grep -n WARNING file1 | cut -d":"...

You can try ckyorn binary....

#!/usr/bin/ksh
echo "test"
VAR=`ckyorn -d y -p "Do want to process it"`
if [ $answer = "y" -o $answer = "Y" ] then
cat/etc/passwd
who | who -l
ps -e | wc -l...

sed 's/\(mfr\)/\1ttmmpp/g' a1 | sed 's/\(ppp\)/mfr/g' | sed 's/\(mfrttmmpp\)/ppp/g'

It may also work

You can design a common script which inculdes your condtions to call consecutive scripts and put that common script in cron.

Or In cron, Mention && operator to execute a job if the first job gets...