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wooo whooo , thanks !

thanks

date +%m | sed -e 's/0//g'

Seems to do the right thing

Thanks. I will try it ...

FYI - for testing purposes you could use hourOfDay=$(date +%m), to get the month "04".

Thanks !
joe

Hi,

I am having the following problem.

test > hourOfDay=06 ; delayTime=$(((9-$hourOfDay)*60)) ; echo $delayTime
180
test > hourOfDay=07 ; delayTime=$(((9-$hourOfDay)*60)) ; echo $delayTime...

Thanks !
that is perfect.

(sorry about the grep and sort, It didn't click off hand of how to get ls to do this.).

the line you gave gives me exactly what I want. I just have to get add it to...

OK,

$ls -1t | grep ^suite6 | sort
suite6_dev_1.125/
suite6_dev_1.126/
suite6_dev_1.127/

This gets me the list of files I am interested in.
I want to now remove all but the last 2...

After further thought that didn't quite work.
The actual directory listing looks like this ( I "bolded" the directories of interest):

$ls -1t
suite6_dev_1.127/...

Thanks ! Great start.

there are other files in the directory other than the ones I want to delete, so I need to do some further work, but it is a good start, and much easier than I envisioned.
...

Hi.

I need a script (either bash or perl) that can delete previous versions of files.

For instance, from our continuous build process I get directories such as

build5_dev_1.21...

well, I did not solve the problem, but I got around it by putting all of my processing in the "if" statement and performing an exit 0 after I did what I needed to. Would be nice to know what I am...

Yes
"
The input file looks like this:

commands will be executed using /bin/bash
job 1237304740.a at Tue Mar 17 11:45:40 2009"

and you can see in the execution
"+ echo 'AT Job ID =...

Hi.
I have the script shown below. If I execute it form the command line it seems to work properly, but when I fun it using the unix "at" command
"at -m now < ./kill-at-job.sh"
It appears to...