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I think reading user input instead of passing it as an argument is just the ticket. Thanks for your assistance.

Would there be any way to do it inside the script without protecting (that way I don't have to ask people running the script to remember to quote it out) ?

Here was the final complete code if anyone was interested. I know the sleep commands aren't needed, and neither is the for loop, but they make it feel like the program is taking a few seconds to do...

What about just this where filename.ksh is the name of the script you created:
./filename.ksh
or this
sh; ./filename.ksh

the command sh invokes the sh shell... it looks like you are trying to...

I'm trying to create a bash script that takes a URL as one of its arguments like this:

./script.sh http://url.cfm?asdf&asdf=234
variable=$1
echo $variable


I'm having trouble storing the...

I thought single quotes too, and that didn't work right. Here is what actually worked after much trial and error:


sed -n s/'!'/'\\''!'/p

#!/bin/bash

wget -O tmp.tmp "YouTube - Pretty Woman- Vivian's Goes Shopping!"
temp=`grep 'one&video_id=' tmp.tmp | sed "s/.*one&video_id=\(.*\)'\;.*/\1/"`...