Search Results

Thank you very much ! :b:

On AIX the -d option don't work. I will use the Perl command.

Hello all,

How can I get a timestamp with 15 min more than current time ?
I want to get it like YYYYMMDD-HHMMSS

Thank you for your answers :b:

Regards

$ cat info.txt
Major=1
Minor=2
Sub=3
Path=4
$ . ./info.txt
$ echo $Major.$Minor.$Sub.$Path
1.2.3.4
$

In Korn Shell:
#!/bin/ksh

if [ ! $# -eq 2 ]
then
echo "Usage: $(basename $0) <filename> <target directory>"
exit 1
fi

fname=$(basename $1)
current=$(pwd)

cd $2
...

The "command not found" is a problem with bin/csh vs /bin/csh ...
This is the subject, so I just answered on the subject ...

It's very difficult in script shell to manipulate line with spaces ... Try this code and launch it like : ./myscript infile outfile

Assume value 441/442 on positions 116 and 130.
If some lines...

Check for your errors yourself ... :D

#!/bin/csh
# This script will accept a file name as one argument and the word
# read, write or execute as the second argument
# On top of that, it will...

Try this:
heading=`sed -e 's/$/<br \/>/' file2 > /tmp/file2.$$ ; cat /tmp/file2.$$ ; \rm -f /tmp/file2.$$`
para=`sed -e 's/$/<br \/>/' file3 > /tmp/file3.$$ ; cat /tmp/file3.$$ ; \rm -f...

#!bin/csh -> #!/bin/csh ??? :D

After, I don't like csh so ...

Use the GNU utilities for Win32 (http://unxutils.sourceforge.net/)
You'll find head.exe, ls.exe, ... :eek:

If you have the "rev" command, use gppcj solution.
Otherwise, use awk, because with cut, you must know the number of fields to get the last one.
If the delimiter is a / you can use "basename"...

who -q | wc -w

#!/bin/ksh

while read line
do
echo $line | cut -c1-10 | sed -e 's/\// /g' | read D M Y
echo $Y/$M/$D$(echo $line | cut -c11-)

done < infile

-d Delete all occurrences of input characters that are specified
-s Replace instances of repeated characters with a single character

Delete vs replace by a single char.

Did you try "-ds"...

Is there any data in ~/builds/scripts/at-job.log ???

who | cut -f1 -d' ' | sort | uniq

Replace $NF by your column number :
awk '{$2=NR}{print}' infile
ATOM 1 N PRO A 15
ATOM 2 CD PRO A 15
ATOM 3 HD1 PRO A 15
ATOM 4 HD2 PRO A 15
ATOM 5 CA PRO A 15
ATOM 6 HA PRO A 15
ATOM 7 CB...

Well, before you ask for the "0" case ... :D :
read x

while read line
do
echo $line | read a b c d

if [ "$a" = "$x" ] || [ "$x" = "0" ]
then
( IFS=-
printf ' 1\n 20\n 0\n 0\n 1\n 1\n 7\n...

Sorry, I didn't see this -second- bug ... ;)
while read line
do
echo $line | read a b c d

if [ "$a" = "$x" ]
then

Result:
Please enter the Test Day or 0 for all days:
1
X is now equals...

Try this:
while read line
do
echo $line | read a b c d

Usage: java [-options] class [args...]
(to execute a class)
or java [-options] -jar jarfile [args...]
(to execute a jar file)

Using xpg4' sed on Solaris with "sed 's/[[:space:]]\{2,\}\|//g'" gives for me
a bsa df32323
sf saafs sdf4333
a b cadfsa dsf23 32|23
Must use "sed 's/[[:space:]]\{2,\}\|/|/g'" (just add | before...

My command work under Solaris. I think you are under Mandriva 2009 ?
So, the recursive option of the 'rm' command is '-R' and not '-r'.

Try this:$ find /path/to/data/* -name data -type d -ctime 0 -exec rm -rf {} \;:D

Hummmm ... you translate "/" in "\n" and after you want to "cut" with the "/" as delimiter ... :rolleyes:

Try this :$ path=/first/second/third/fourth
$ var=$(dirname $path)
$ echo $var...