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I guess my explanations were not great, 'cause ur code works great. 10x and sorry for the trouble

well, as I said I need to have the result of $(echo "$x" | cut -d"~" -f1) stored into a variable, then to echo this one. but quoting the input for echo seems not to work inside $(...); i.e echo "$x"...

sorry to be a pain in the behind, but eventually anybody has a solution?

right; my problem is that I need to assign the result to a var then echo it;
like:

var="hello * world~something"
var2=`echo "$var" | awk -F~ '{print $1}'`

echo $var2

actually I've simplified it a bit: I need to assing echo "$x" | cut -d'~' -f1 to a variable, then echo it; that's why the double echo

in my hp-ux it seems cut works with ~ unquoted

I have something like this:

x="hello * world~something"

I know for verbatim printing I need to do echo "$x", but I need also to cut just 1st field from the string (delimiter is ~).

I'm...