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Sorry, a typo on my part was causing the problem.

Thanks for your help,

Susan

Thanks to both of you but unfortunately I am still getting the error message "grep: 0652-033 Cannot open ." for both of your options. I tried ${vOracount} but that made no difference.

I also...

All I want to do is find out if the string 'NO' is in a file by checking for a return code of 0 if there is a match. The grep works fine on the command line directly naming the file but I am...

Do you have any recommendations for books to read or websites to visit that cover syntax information about when to use square brackets, brackets, braces, apostrophes, quotation marks etc. in a shell...

An extra \ does the job.

sed "${vLineNumber}c\\
replacement text" "$vScriptName" > $vScriptName2

I got the idea from Re: Illegal variable name & carriage return...

I tried
sed "${vLineNumber}c\
.run logon.txt" "$vScriptName" > $vScriptName2

and received this message

sed: 0602-404 Function 3c.run logon.txt cannot be parsed.

vLineNumber is...

Sorry to be a pain but I now want to use a variable instead of a line number in my script and I am getting nowhere fast with combinations of " and ' and `.

What would be the correct way to write...

That's great - it works a treat. Thank you very much.

All the best,

Susan

I get
sed: 0602-404 Function 3c "replacement txt" cannot be parsed.

for sed '3c "replacement txt"' filename.txt

Regards,

Susan

I have now - the response was
sed: 0602-404 Function 3creplacement txt cannot be parsed.

I put your script

>sed 3c"replacement txt" filename.txt

directly into the command line

Is...

I know that I want to entirely replace line 3 in my file filename.txt. I have tried all sorts of variations of

sed 3,3,c\replacement stuff\ filename.txt with no success.

about the only thing...