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Thanks so much for your help, however neither of those work for me. I am running on Sun Solaris if that makes any differance and my sed is from 2005 it says. Tried gsed as well to no avail. Any...

So here is my problem:

I need to do a sed search and replace on the following:

variable_blah_STATUS replaced with "replace string".

sed 's/variable_blah_STATUS/replace string/g' works...

awesome, works great with unzip -l...thanks!

I am listing the contents of a zip file and then grepping for a specific string ie: filename.a to get a line like: 309753 10-18-08 15:20 etc/filename.a

The etc/filename.a is the path the...

ah just got it, nevermind then something like sed 's/.*\([0-9]\{3\}-[0-9]\{4\}-.*\).*/\1/' works great.

I am using sed to find a pattern in a line and then I want to retain the pattern + the rest of the line. How is this possible? ie:

line is: 14158 05-15-08 20:00 ...

awesome, thank you! There went 45 min of my life that I will never get back, hah!

Hello, I have a file path such as: /path/to/whatever/30 and I want to get the number off the end. My problem is that there might be other numbers in the path and the last number can be 1 or 2...

I got it, my directory path also has a timestamp at the end of it and I didn't enclose it with quotes and it used some <>'s Newbie mistake I guess. Thank you much for all your help...certainly made...

Thank you so much for your reply. Looks like it should work, I am piping
/usr/dev/blah/Arch/release/812-1235-P05/files/list which is from a previous grep command into sed so like grep...

Hello, I am very new to shell scripting and have a directory path such as:
/usr/dev/blah/Arch/release/812-1235-P05/files/list and I want to output:

812-1235-P05

I think using sed with a regex...