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bash-2.05# for i in *.dbf
do
/usr/local/gpg2/bin/GPG2 -o $i -d $i.gpg
done

usage: gpg [options] --decrypt [filename]


it need the file name correctly

i am not sure how will this work.

i could do something like

for i in `ls -l ./*.dbf | grep -v "^gpg"' `
do
/usr/local/gpg2/bin/GPG2 -o $i -d *.gpg
done


but when i run this i get...

Hi Gurus

I have to write a script which does something like this

/usr/local/gpg2/bin/GPG2 -o arch_696354351_1_23.dbf -d arch_696354351_1_23.dbf.gpg
/usr/local/gpg2/bin/GPG2 -o...

Thanks man !!

if [ $# != 3 ]
then
echo "Syntax: $0 <sid> <COLD/HOT> <DEST>"
exit
fi



if [ $# != 3 ]--------------what does this mean???
echo "Syntax: $0 <sid> <COLD/HOT> <DEST>"---pls explain...