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I want to replace the last to characters to OO
i have these files

456464
213131
785521
231645
021321
.....

i DOnt have any idea on this please help..

why is that it took to much time to run the code?
do you have any suggestion how this can be optimized

for example i have this:

123456
456778

i want to change the last two digits to 00

how can i do these please help

I have these two files:
file1
NPANXX|BILLDATE|DIVCODE|COMID|RAO|LIKECODE|BOSS|SORD|STATECODE|
087001|BP01|H|SWBT| |041|IMR6|IMSR6|AR|
087002|BP03|H|SWBT| |042|IMR6|IMSR6|AR|...

sed -e '1s/\|$/\|LIKECODE \|/g' -e 's/^090.*$/&CF5857\|/g' -e 's/\(^087.*H\|\)(.
...\)\(.*\)/\1PHI\3/g' dryloop.txt > drdry.txt
this is what i typed

Sorry myfault but an error appeare it says that the function cannot be parsed

Thanks.
Why is that it didn't create any output file?

I have this code:
#!/bin/sh
awk 'BEGIN
NR == 2
repl[087*] = "PHI"
$4 = repl[$4]
print $0 'dryloop.txt

and this code:
#!/bin/sh
sed -e '1s/\|$/\|COMID\|/g' -e 's/^087.*$/&PHI\|g'...

thanks vidyarhar85 it works great. Thanks alot.
can you please explain your im quite confuse
thanks alot

Thanks. but TEST column should only be added at the first line

what if i want to save it in a new file?

it still doesn't work ..why is tha?

this is what i've done to insert new column but it does not work.
cat hl.dsldryloop | awk -F\|'{print $1"|"$2"|"$3"|"$4"|"$5"|"$6"|"$7"|"$8"|"$9"|TEST|" } ' >file.txt

I have this file:

NPANXX|BILLDATE|DIVCODE|COMID|RAO|LIKECODE|BOSS|SORD|STATECODE|
087001|BP01|H|SWBT| |041|IMR6|IMSR6|AR|
087002|BP03|H|SWBT| |042|IMR6|IMSR6|AR|
087003|BP05|H|SWBT| ...