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Well,.
I came with this solution, but litle bit messy i think

set -A dlm -- 5 12 17
inc=0
while [ $inc -lt ${#dlm
} ] ; do
cmd="$cmd s/^(.{${dlm[$inc]}}),(.*)/\1;\2/g ;"
let inc=inc+1...

but the result not match with requirement,.
the script u gave same like i use
tr ',' ';'

is there any clues to change commas in specified position within a line??

anybody can help??

in my input sample
aaaa,aaa,aa,aaaa,aaaa aa

i just want to change commas in position 5,12,17 into semicolon..
no change in data

i try to make an array and make a script, see below

set -A...

not change the 'a' letter to 'c' like u mention above,.
and i modify to
echo "aaaa,aaa,aa,aaaa,aaaa aa" | awk -F "," '{printf "%s;%s%s;%s;%s,%s\n", $1,$2,$3,$4,substr($5,0,4),substr($5,6,2)}'
...

what i'm concern is, replace all commas delimiter to semicolon except several column
e.g
i have a file contains two lines:
aaaa,aaa,aa,aaaa,aaaa aa
cccc,ccccc ,cccc,cccc,cc

and i want change...

Hi All,
I have problem to solve
aaaa,aaaaa,aaa,aaaa,aaa,aa ,aa
bbbb,bbbbbbbbb,bbbb,bbbbb ,bb

to
aaaa;aaaaa,aaa ;aaaa;aaa,aa ;aa
bbbb;bbbbbbbbb;bbbb;bbbbb ;bb

i try use sed to find and...