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#!/usr/bin/ksh
awk '
{
dial_date="May 26, 2010"
print dial_date
"date -d "dial_date " +%d%m%Y" | getline aa
print aa
} END {}' < "input"
exit 0


Messge...

I tried :
`"date -d "dial_date " +%d%m%Y"` | getline aa
I got an error : sh -c

Hi,

I am working on Redhat GNU linux


#!/usr/bin/ksh
awk '
{
dial_date="May 26, 2010"
print dial_date
aa ='`date -d '"dial_date"' +%d%m%Y`'
print aa
}...

hi there,
date -d '1 week ago'
or
date -d '7 days ago'
will give the date and time of exactly a week ago.
You can use '1 month ago' 'yesterday', '2 hours ago', etc..
For future dates, use...