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omg, isn't there a simple way to do this?

how can i make awk recognize the second field as a pattern?

this doesn't work:
awk -v numbers="$numbers" '{if (numbers ~ /$2/) print $0, "bla bla"}'...

forgot to mention - the line i wrote didn't work i guess it has to do with the syntax

and yes, what i meant to do was:
if the line contains one of the numbers (in the 2ed field), then print $0,...

hi,

let's say $numbers = "324 350 587" an so on...
what i'm trying to do is this:

awk -v numbers="$numbers" '{if (numbers ~ /$2/) print $0, "bla bla"}' file

# file looks like this:
214...