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Thanks for the reply, my current code:


elif [ "$1" == "-r" ]
then
echo "Enter the new name: "
read name
echo "Enter the new address: "
read address
echo "Enter the new phone number: "...

It seems like I have tried every possible thing. :( when I do exactly what you suggested it just acts like a cat (when the user is inputing information, it keeps going until i press ctrl+d). If I...

Thanks for the reply, i really do appreciate all help.

I couldnt get that to work though, as i encountered many different problems

I currently have:

#delete the line that include the name...

thanks very much for the reply

line = $(grep $2 dirInfo) #Gives the error: line: command not found
line = 'grep $2 dirInfo' #Gives the error: line: command not found

Is there a different...

elif [ "$1" == "-r" ]
then
echo "Enter the new name: "
read name
echo "Enter the new address: "
read address
echo "Enter the new phone number: "
read phonenumber
#ERROR line = 'grep $2...

WOW thank you so much! Is there any way to edit it in my code so I dont have to put the quotation marks in the input?

yes i believe so.


#Doesnt Work
elif [ "$1" == "-p" ]
then
grep "$2" dirInfo


-bash-2.05b$ ./phonebook -p (324)343-3421
-bash: syntax error near unexpected token `('

It seems as though...

Thank you so much for your reply. Sorry about the spelling!

To check the last name (input is the first letter) this worked!:
grep '^'"$2" dirInfo

One of my biggest questions is why the grep...

Right now if I have a file that has the following information (with : as the delimiter)

name :address :phone number

I need to be able to do the following commands:
-n search for a name
-p ...