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Hi Guys,

I've to print a block of lines that starts with a keyword CREATE and ends with ; using awk command is there a way to do this?

awk '{if ($1=="CREATE" ) {print $0}}' filename.

This...

Hi,

Earlier I have mentioned the command wrongly.

Input:
$ cat samp
1234 "6734" "DSS" "8887578384" "ABC PRIVATE LMT REGNO 6" 3245

Output of the unix command:

$ sed -e 's/ / /g' -e 's/...

Hi All,

Thanks for the detailed explanation.

I was just wondering how we can handle multiple spaces in such case. Please find the below example

1234 "6734" "DSS" "8887578384" "ABC PRIVATE...

Hi,

Can you please help me explain what the second statement in sed does

's/\("[^"|][^"|]*\)|\([^|][^|]*|\)/\1 \2

I didnt get why "[^"|] and ^| is specified twice after special/escape...

Excellent answer It worked...

Many thanks I know the command is bit long but ever lasting one..

This site is kewl I'm loving it...

Thanks buddy..
Dude :b:

Hi,

This doesnt work :mad: any other inputs...

Also one more thing to add..

I should have double codes with in the strings. As I said earlier.. the o/p should be like below
...

Hi All,

Can some one help me in providing the unix command to ignore the "" in a line. To explain in detail

I have a file which is space delimited.

Ex
1 2 3 4 "hello" "rock dude" 5 6 7
...